Re: Expected seismograph output: For the benefit of estimating what amplitude a PSN seismograph should expect to detect from an earthquake at a given distance, we use the generic magnitude formula: Ms = log(A/T) + 1.66*log(distance) - 0.18 where A is the peak-to-peak ground amplitude at the seismograph in nanometers (10^-9 meters), T is the period in seconds, the distance is in degrees ( 1 deg = 111 km, and the constant -0.18 is an attenuation adjustment. which is solved for the amplitude: A = T * 10^[Ms -1.66*log(dist) + 0.18] Then selected combinations of Magnitude and distance are used to determine the seismograph amplitude in nanometers (m * 10^9), which are converted to peak velocity by multiplying by w (omega) = 2*pi*f, where f = 1/T. The possibilities are fortunately limited by the effect of dispersion of the seismic wave, namely that the wave period increases with distance, so a close quake will have periods of less than 1 second, while a distant event will arrive with periods in excess of 20 seconds. While the possibilities are endless, typical distance-period combinations are selected. Other limitations are presented by the expectations of the seismograph or seismometer-digitizer. Since these are velocity-recording systems, we will assume a constant VBB output of 1000 volts/meter/second (v*sec/m) for all periods/frequencies. THis then presents dynamic limits of a maximum voltage of 10 volts and a background noise level of 1 millivolt. Of course for a reasonable signal-to-noise ratio of 100 to 1,. the system noise floor must be 10 microvolts or less. Your particular seismograph parameters may be different, but the generalities here can be scaled appropriately. Also, the generic magnitude formula is not exactly applicable for nearby ( 100 to 200 km) quakes; special formulas will expect up to twice the amplitude since the attenuation is a fractional power of the distance. In the table below, the velocity in microns/second has the same value as the seismometer output in millivolts if the sensitivity is 1000 volts/meter/second. A "*" indicates a clipped output over 10 V. Magnitude Amplitude Velocity/output acceleration Ms microns u/sec = millivolts percent of g Distance: 0.1 degree (11 km), period: 0.25 seconds (4 hz). 3 17 435 0.11 4 173 4347 (ie 4.3volts) 1.11 5 1729 43469* 11.14 Distance: 1.0 degree (110 km), period: 0.50 seconds (2 hz). 3 0.76 9.5 0.0012 4 7.6 95 0.012 5 76 951 0.12 6 760 9510 1.12 Distance: 3 degrees (330km), period: 0.7 second (1.43hz). 3 0.17 1.5 0.0001 4 1.7 15 0.0014 5 17 154 0.014 6 171 1535 0.1406 Distance: 9 degrees (999 km), period 1.0 second (1.0hz). 3 0.039 0.247 4 0.39 2.478 5 3.9 24.78 0.0016 6 39.4 247.8 0.016 7 394.4 2478 0.1589 Distance: 30 degrees (3330km), period 15 seconds 4 0.8 0.336 5 8.0 3.36 6 80 33.6 7 802 335.9 0.00143 Distance: 45 degrees (4995 km), period 15 seconds 4 0.4 0.17 5 4.1 1.71 6 40.9 17.1 7 409 171.3 0.00073 Distance: 90 degrees (9990km), period 25 seconds 5 2.16 0.542 6 21.6 5.42 7 215.7 54.22 8 2157 542.17 0.00139 Distance: 135 degrees (14985 km), period 25 seconds 5 1.1 0.27 6 11.0 2.76 7 110.0 27.65 8 1100.5 276.58 For example, if the quakes in Turkey are about 90 degrees from St. Louis, I would estimate that a Ms 7.0 would have a peak-peak amplitude at 25 seconds of about 54 microns/second. Since the recording sensitivity here is 5290 Volts/meter/second (5.29mv/micron/sec), the digitizer should see 285 millivolts (peak voltage), which means that it clips on the 200mv scale, which it did for the 7.2 yesterday 12 Nov. Regards, Sean-Thomas _____________________________________________________________________ Public Seismic Network Mailing List (PSN-L)
Larry Cochrane <cochrane@..............>